Searching a table for cells that contain a word and returning the entire row using Sqlite3 module in Python

Question is the same as above, I just don't know how to get it to print the 4 rows that contain London. Here is my code for reference:

def db():
    import sqlite3
    con = sqlite3.connect('weather.db')
    global cur
    cur = con.cursor()
    cur.execute("CREATE TABLE if not exists weather(City text,Country text,Season text,Temperature int,Rainfall int)")
    weather_list = [['Mumbai','India',1,24.8,5.9],['Mumbai','India',2,28.4,16.2],['Mumbai','India',3,27.9,1549.4],['Mumbai','India',4,27.6,346.0],['London','UK',1,4.2,207.7],['London','UK',2,8.3,169.6],['London','UK',3,15.7,157.0],['London','UK',4,10.4,218.5],['Cairo','Egypt',1,13.6,16.5],['Cairo','Egypt',2,20.7,6.5],['Cairo','Egypt',3,27.7,0.1],['Cairo','Egypt',4,22.2,4.5]]
    for items in weather_list:
        items = tuple(items)
        cur.execute("INSERT INTO weather VALUES(?,?,?,?,?)",items)
        con.commit()    
    for items in cur.fetchall():
        print(items)

#4
def db_changes():
    db()
    global cur
    cur.execute('SELECT City FROM weather WHERE City=?',(['London']))
    for record in cur:
        print(record)