I have something like
$tableName = "table1";
$sql ="CREATE TABLE "'.$table1.'"
(ID INT PRIMARY KEY NOT NULL,
NAME TEXT NOT NULL,
AGE INT NOT NULL,
ADDRESS CHAR(50),
SALARY REAL)";
but it doesnt works
Edit: I already have answer it's
$sql ="CREATE TABLE `".$tableName."`
(ID INT PRIMARY KEY NOT NULL,
NAME TEXT NOT NULL,
AGE INT NOT NULL,
ADDRESS CHAR(50),
SALARY REAL)";
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